SOLUTION: This is not from a textbook, just from a worksheet my teacher made up. The question is : 4logx = 4 I think that you can move the first 4 to make the question logx^4=4 , but that

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: This is not from a textbook, just from a worksheet my teacher made up. The question is : 4logx = 4 I think that you can move the first 4 to make the question logx^4=4 , but that      Log On

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Question 165416: This is not from a textbook, just from a worksheet my teacher made up.
The question is : 4logx = 4
I think that you can move the first 4 to make the question logx^4=4 , but that is as far as I have gotten.
Thank You For Your Help!
Found 2 solutions by nerdybill, jim_thompson5910:
Answer by nerdybill(6962) About Me  (Show Source):
You can put this solution on YOUR website!
Remembering that:
log(100) = 2
or
100 = 10^2
.
Looking at your problem:
4logx = 4
logx = 1
x = 10^1
x = 10

Answer by jim_thompson5910(28595) About Me  (Show Source):
You can put this solution on YOUR website!
Note: I'm assuming that the base is 10


4%2Alog%2810%2C%28x%29%29=4 Start with the given equation


%28cross%284%29%2Alog%2810%2C%28x%29%29%29%2F%28cross%284%29%29=cross%284%29%2Fcross%284%29 Divide both sides by 4


log%2810%2C%28x%29%29=1 Divide and simplify


10%5E1=x Rewrite the equation using the property: log%28b%2C%28x%29%29=y ====> b%5Ey=x


10=x Raise 10 to the first power to get 10


So the solution is x=10