SOLUTION: log(2)8, log(4)8, log(8)8, log(16)8, log(32)8, log(64)8, log(128)8 find an expression of the nth term of the sequence. write expression in p/q form. justify using technology.

Algebra.Com
Question 161686: log(2)8, log(4)8, log(8)8, log(16)8, log(32)8, log(64)8, log(128)8
find an expression of the nth term of the sequence. write expression in p/q form. justify using technology.

Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
Find the nth term ():
,,,,,,,...
You can see that the base of the logarithms is always 2 to some power, and the power of 2 goes up like this, starting with the first term :,,,,,,,..., so for the nth term the base would be:
Now you can write the nth term as:
Now if you rewrite this in exponential form, you'll get:
Substitute to get:
Now since the bases (2) are equal, the exponents must be equal, so...
Divide both sides by n to get:
This is the expression for the nth term expressed in form.

RELATED QUESTIONS

log(8)2+Log(8)32 (answered by Alan3354)
Log 8 + Log 32 - Log 2 (All in base... (answered by Edwin McCravy,greenestamps)
log 8 + log 5 - log... (answered by jim_thompson5910)
log 8 + log 5 - log... (answered by checkley77)
simplify log 8 + log... (answered by MathLover1)
Log base 8 of 16+ log base 8 of... (answered by nerdybill)
Log base 8 *log base 4 *log base 2... (answered by Alan3354)
Solve the equation {{{log(16,(x))+log(8,(x))+log(4,(x))+log(2,(x))=6}}} (answered by jim_thompson5910)
hello .... log 8... (answered by rapaljer)