SOLUTION: log(x) + log(2x) = 10 Im really confused on this question. Ive been trying this: log(x(2x))=10 log(2x-x^2)=10 but after that im not sure what to do next. Any help would

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: log(x) + log(2x) = 10 Im really confused on this question. Ive been trying this: log(x(2x))=10 log(2x-x^2)=10 but after that im not sure what to do next. Any help would       Log On

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Question 155529: log(x) + log(2x) = 10
Im really confused on this question. Ive been trying this:
log(x(2x))=10
log(2x-x^2)=10
but after that im not sure what to do next. Any help would be great. Thank you!!
Answer by Earlsdon(6103) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
Log%28x%29%2BLog%282x%29+=+10 Apply the "product rule" for logarithms.Log%28a%29%2BLog%28b%29+=+Log%28a%2Ab%29
Log%28x%2A%282x%29%29+=+10 Simplify the left side.
Log%282x%5E2%29+=+10 Apply the power rule for logarithms. Log%28a%5En%29+=+n%2ALog%28a%29
2%2ALog%282x%29+=+10 Divide both sides by 2.
Log%282x%29+=+5 Convert to the equivalent exponential form:Log%5Bb%5D%28x%29+=+y--->b%5Ey+=+x, so...
10%5E5+=+2x
100000=+2x Divide both sides by 2.
highlight%28x+=+50000%29