SOLUTION: 2logx-log7=log112
Algebra.Com
Question 151169: 2logx-log7=log112
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve for x:
Apply the power rule for logs to the first term.
Now apply the quotient rule.
Apply the identity rule: If then
Multiply both sides by 7.
Take the square root of both sides.
Only the positve value of the square root is valid.
Check:
Substitute x = 28.
RELATED QUESTIONS
2logx-log7=log112 (answered by edjones)
solve the logarithmic equation... (answered by nerdybill)
how do you condense log7+2logx-5logy
(answered by stanbon)
2logx=2 (answered by Alan3354)
2logx+log11 (answered by stanbon)
2logx+log5 (answered by Alan3354,ewatrrr)
10^2logx=2x (answered by longjonsilver)
2log4+2logx=log32 (answered by rapaljer)
2logx+3logy-6logxy (answered by nerdybill)