SOLUTION: solve for x. 2 log2 x - log2 (x+4)= log2 2

Question 150019: solve for x.
2 log2 x - log2 (x+4)= log2 2
Found 2 solutions by stanbon, Fombitz:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2 log2 x - log2 (x+4)= log2 2
--------------
Keep the base in mind.
2 logx - log(x+4) = log2
logx^2 - log(x+4) = log2
log[x^2/(x+4)] = log2
x^2/(x+4) = 2
x^2-2x-8 = 0
(x-4)(x+2) = 0
x = 4 or x = -2
-------------
x cannot be -2 as that would make the problem statement meaningless.
---------------
Final solution: x = 4
===========================
Cheers,
Stan H.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Logarithm rules

.
.
.

Take the inverse log of both sides.

First solution

Second solution

Second solution is not allowed since is not defined.

RELATED QUESTIONS
Log2 (x+2) = log2 3-log2... (answered by Alan3354,MathTherapy)
log2(x + 2) + log2(x - 4) =... (answered by lwsshak3)
Solve log2(x+2) =... (answered by stanbon)
Solve: Log2(2) +log2(x+3)=5 (answered by stanbon)
solve for x: log2(x+2) +... (answered by lwsshak3)
log2(x - 2) + 5 = 8 - log2... (answered by mukhopadhyay)
log2(x - 2) + 5 = 8 - log2... (answered by Nate)
log2(x - 2) + 5 = 8 - log2... (answered by jim_thompson5910)
log2(3x-2)-log2(x-5)=4 (answered by robertb)