SOLUTION: Write as a single logarithm: 5/6log(x) + 12log(y) - 6logx - logy

Algebra.Com
Question 148320: Write as a single logarithm:
5/6log(x) + 12log(y) - 6logx - logy

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
(5/6)log(x) + 12log(y) - 6logx - logy
Rearrange and factor to get:
[(5/6)-6]logx + 11logy
[-31/6]logx + 11logy
= log[x^(-31/6)*y^11]
= log[y^11/x^(31/6)]
========================
Cheers,
Stan H.

RELATED QUESTIONS

Write expression as a single logarithm, 6log x + 2log... (answered by Alan3354)
write as a single logarithm=6log base 5 X + log base 5 Y (answered by jsmallt9)
Write as a single logarithm... (answered by stanbon)
write the expression as a single logarithm. 4log... (answered by vleith)
6log[m](8x+1)+((1)/(4))log[m](x+8) write as a single... (answered by stanbon)
Write 2/3[logt-5logn+logy] as a single... (answered by stanbon)
Using laws of logarithms, write the expression below as a single logarithm.... (answered by fractalier)
Math help with steps pls. Write the expression as a single logarithm:... (answered by MathLover1)
How would I write the following expression as a single logarithm:... (answered by nabla)