# SOLUTION: log5 (to the power of 5) (x+3)+log5(big 4)=log5(big 36) once again its: log5(x+3)+log5 4= log5 36

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: log5 (to the power of 5) (x+3)+log5(big 4)=log5(big 36) once again its: log5(x+3)+log5 4= log5 36      Log On

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 Question 147773: log5 (to the power of 5) (x+3)+log5(big 4)=log5(big 36) once again its: log5(x+3)+log5 4= log5 36Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!All logs are the same base, 5. The sum of logs on the left side means the 2 terms are multiplied. That is, the sum of 2 logs is the log of the product of the 2 terms. So, log(x+3) + log(4) = log(36) (Regardless of base as long as they match) log[(x+3)*4] = log(36) If the logs are equal, the terms are equal. (x+3)*4 = 36 4x+12 = 36 4x = 24 x = 6 Check: (6+3)*4 = 36.