SOLUTION: 1) write log7 49=2 in exponential form. 2) use the change of base formula( property 10.9) to solve for x; x=log3 90 3) solve for x: 9/(4x)+1/3=5/(2x); (x^-1=4/3)

Question 145425: 1) write log7 49=2 in exponential form.
2) use the change of base formula( property 10.9) to solve for x; x=log3 90
3) solve for x: 9/(4x)+1/3=5/(2x); (x^-1=4/3)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1) write log7 49=2 in exponential form.
7^2 = 49
-------------------
2) use the change of base formula( property 10.9) to solve for x; x=log3 90
x = [log90]/[log3]
x = 4.09590...
--------------------
3) solve for x: 9/(4x)+1/3=5/(2x); (x^-1=4/3)
[9/(4x)] + [1/3] = [5/(2x)]
Multiply thru by 12x to get rid of the fractions:
27 + 4x = 30
4x = 3
x = 3/4
-----------------
(x^-1=4/3)
x = 3/4
===========
Cheers,
Stan H.

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