SOLUTION: please help me solve this equation: logx base 2 + log2 base x=2
Algebra.Com
Question 141177: please help me solve this equation: logx base 2 + log2 base x=2
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve this equation: logx base 2 + log2 base x=2
log2/logx + logx/log2 = 2
(log2)^2 + (logx)^2 = 2(log2)(logx)
(logx)^2 -2(log2)(logx) +(log2)^2 = 0
Factor:
(logx-log2)^2 = 0
logx = log2 twice
x = 2 (twice)
===================
Cheers,
Stan H.
RELATED QUESTIONS
Please help me solve this task:
Sqrt(log2((2x-3)/(x-1)))<1
log2 is logarithm base (answered by rothauserc)
please help me solve the following logx with base 2 + log base2(x+5)-2log 3 base... (answered by scott8148)
Please help me solve this problem: log16x+log4x+log2x=7. I know you have to use the... (answered by lwsshak3)
Please help me solve this equation: {{{ 2log base 3(x+4)-log base 3(9)=2 }}}
(answered by MathTherapy)
Please help me solve this equation: {{{ log base 4(x^2+6)=log base 4 (5x)... (answered by josgarithmetic)
Solve
a) log(base 8)(x+1) - logx = 2
Can you please help me out? Thanks so much in... (answered by jim_thompson5910)
This equation is on a work sheet that I need to solve:
log2 (5X+7) - log2 (X) = 2... (answered by Earlsdon)
Solve the paired simultaneous equation
logx (base 2) + logy (base 2) = log36 (base 2)... (answered by MathLover1)
Please help me solve this problem:
log2 x+ log2 (x+2)-log2... (answered by lwsshak3)