SOLUTION: How you you solve these logs finding x,b or y logBASE3^y=2 and logBASEb^32=5?

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Question 140852: How you you solve these logs finding x,b or y
logBASE3^y=2 and logBASEb^32=5?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
logBASE3^y=2 and logBASEb^32=5?
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log3 y 2
y = 3^2 = 9
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logb 32 = 5
b^5 = 32
b = 2
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Cheers,
Stan H.