SOLUTION: How do i solve log64^8=x
The answer is 1/2 but how do you come about that answer?
Also log5^1/5=x & log7^square root of 7=x
These have me so confused.
Algebra.Com
Question 140699: How do i solve log64^8=x
The answer is 1/2 but how do you come about that answer?
Also log5^1/5=x & log7^square root of 7=x
These have me so confused.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'm assuming that the problem looks like this: ???
Start with the given equation
Rewrite the left side by using the change of base formula. Remember the change of base formula is
Rewrite 64 as
Rewrite the denominator using the identity
Divide and cancel like terms
Simplify
So the answer is
Start with the given equation
Rewrite the left side by using the change of base formula.
Rewrite 5 as . Notice how
Rewrite the denominator using the identity
Cancel like terms
Simplify
Reduce
So the answer is
Start with the given equation
Rewrite as
Rewrite the expression using the identity
Take the log base 7 of 7 to get 1. In other words,
Multiply
So the answer is
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