SOLUTION: Please help me solve this.
Solve for y in terms of x:log2x+log2y=1
This is all i have so far: log2xy=1 and log2 rewrites as b^p=n
So, b=2 p=1 and n=xy
What do i do afte
Algebra.Com
Question 140574: Please help me solve this.
Solve for y in terms of x:log2x+log2y=1
This is all i have so far: log2xy=1 and log2 rewrites as b^p=n
So, b=2 p=1 and n=xy
What do i do after this?
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
log2x+log2y=1
then
log2(xy)=1
then
xy=2^1=2
then
x=2/y
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