# SOLUTION: solve the logarithmic equation. be sure to reject any value that is not in the domain of the original logarithmic expression. Give the exact answer. log2(x-1) = 1 + log2 (x-5)

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: solve the logarithmic equation. be sure to reject any value that is not in the domain of the original logarithmic expression. Give the exact answer. log2(x-1) = 1 + log2 (x-5)      Log On

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 Click here to see ALL problems on logarithm Question 138622: solve the logarithmic equation. be sure to reject any value that is not in the domain of the original logarithmic expression. Give the exact answer. log2(x-1) = 1 + log2 (x-5)Answer by oscargut(891)   (Show Source): You can put this solution on YOUR website!log2(x-1) = 1 + log2 (x-5) log2(x-1) - log2 (x-5)= 1 log2((x-1)/(x-5))=1 (because log(a)-log(b)=log(a/b)) x-1/x-5=2 x-1=2x-10 -x+9=0 x=9 checking: log2(8)=1+log2(4) 3=1+2 Answer: x=9