SOLUTION: ln (x + 6) - ln 10 = ln(x-1) - ln 2
Can you please show me the steps on how to solve this problem along with one like...
log 3x - 2[logx - log(2+y)]
Algebra.Com
Question 137064: ln (x + 6) - ln 10 = ln(x-1) - ln 2
Can you please show me the steps on how to solve this problem along with one like...
log 3x - 2[logx - log(2+y)]
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
ln (x + 6) - ln 10 = ln(x-1) - ln 2
ln[(x+6)/10] = ln[(x-1)/2]
(x+6)/10 = (x-1)/2
Cross multiply to get:
2x+12 = 10x-10
8x = 22
x = 11/4
------------------
Can you please show me the steps on how to solve this problem along with one like...
log 3x - 2[logx - log(2+y)]
Comment: You can't solve this one because it is not an equation:
log3x -2logx + 2log(2+y)
= log[(3x*2+y)/x^2]
=========================
Cheers,
Stan H.
RELATED QUESTIONS
Write as a single logarithm and check with a calculator
a) ln 5 + ln 3
b) ln 2+ ln 10... (answered by jim_thompson5910,stanbon)
Can you please help me with this equation?
ln(x-5)-ln(x+4)=... (answered by scott8148)
Write the following expressions as single logarithm
a) 3 ln x - 2 ln x^2 + ln x
b)... (answered by MathLover1)
log6 (3) + log5 (2) is equivalent to
A 0
B ln(2) * ln (6)
C 1 / ln(6)
D ln(2) / ln (answered by rapaljer)
page 505 # 51
ln x + ln(x-2) =1
can you help me in the steps to solve... (answered by scott8148)
Please show how to condense the following expressions:
2 log 9 + 5 log x + log 1/3
3... (answered by lwsshak3)
1. Solve the following equations
a) log(base 2)x+1 - log(base 2) 2 = log(base 2)5... (answered by lynnlo)
-could you please help me in this problem
solve for x:
ln(x-1)=ln(x-2)-ln... (answered by josgarithmetic)
1. Write x in terms of a , b and c
a) ln x = ln a + ln b - ln c
b) ln x = 2 ln a + 3... (answered by ankor@dixie-net.com)