SOLUTION: x=log2(1+0.871x)

Question 135327: x=log2(1+0.871x)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x=log2(1+0.871x)
I graphed the left side and the right side separately on the same axes.
The points of intersection are (0,0) and (0.63572,0.63572)
Solution: x=0 and approximately x = 0.63572
====================
Cheers,
Stan H.

RELATED QUESTIONS
Log[log(2+log2(x+1))]=0 (answered by Alan3354)

log2(x)+log2(x+1)=log2(6) (answered by LinnW)

Log2 (x+1) - Log2 X= Log2... (answered by htmentor)

Log2 (x+1) - Log2 X= Log2 4 (answered by Gentle Phill)

(log2 x )^2 - log2 x^2 >... (answered by lwsshak3)

Log2 x + log2 x - 5 = 0 (answered by josgarithmetic)

log2(x+1) - log2(x-1) =... (answered by edjones)

Solve with exact solutions log2(x)-log2(3x-1)=0 I only got this far... (answered by oscargut)

log2(h-1)+log2(x+2)=1 (answered by Alan3354,Fombitz)

log2 (x+1) + log2 (x-5) =... (answered by solver91311)