# SOLUTION: log(s+5) = log3x + log(x+1) find the value of x

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 Question 135099: log(s+5) = log3x + log(x+1) find the value of xAnswer by stanbon(57967)   (Show Source): You can put this solution on YOUR website!log(x+5) = log3x + log(x+1) log(x+5) = log[3x(x+1)] Take the inverse-log of both sides to get: x+5 = 3x^2+3x 3x^2+2x-5 = 0 3x^2+5x-3x-5 = 0 x(3x+5) -(3x+5) = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3 ------- Checking: x=-5/3; cannot be as log(3(-5/3)) = log(-5) does not exist. x= 3: log (8) = log(9) + log(4) log 8 = log(9*4) wrong ---------------------------- Conclusion: No solutions =========================== Cheers, Stan H. =================== Cheers, Stan H.