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Start with the given expression
Remember you cannot take the log of zero or of a negative value. So that means the argument

must be greater than zero (i.e. the argument
must be positive)

Set the inner expression greater than zero

Add 5 to both sides

Combine like terms on the right side
So that means t must be greater than

in order for t to be in the domain
So the domain in set-builder notation is
So here is the domain in interval notation:
Notice if we graph

(just replace t with x), we get

notice how the graph never crosses the line

. So this graphically verifies our answer.
and we can see that x must be greater than

in order to lie on the graph