SOLUTION: Solve for x: 2logx=log2+log(3x-4)

Algebra.Com
Question 131546This question is from textbook
: Solve for x:
2logx=log2+log(3x-4) This question is from textbook

Answer by Edwin McCravy(20065)   (Show Source): You can put this solution on YOUR website!

Solve for x: 


Use this rule of exponents on the left side

                     



Use this rule of logarithms on the right side:

                      



Distribute on the right:



Use the rule:

               The equation  =  is equivalent to
               the equation 







 gives solution 

 gives solution 
                        
Edwin
RELATED QUESTIONS

Solve for x 2logx= log2 +... (answered by jsmallt9)
please help me solve for x: 2logx=log2+log(3x-4)... (answered by lwsshak3)
solve for log(3x-1) + log2= log4 +... (answered by lwsshak3)
log (x+20) - log2= log... (answered by MathLover1)
1. 5+2logx=4 2. log(x-2)+log(2x-3)=2logx 3. 4^x+3=7^x 4. log2x + log2 (x+2)=log2 (x+6) (answered by solver91311,stanbon)
Solve for x using logarithms: Solve for x: Log base 4 of(x-6)+ log base 4... (answered by stanbon)
solve logarithmic equation... (answered by rfadrogane)
solve for x log(base 4)(x^2-3x) =... (answered by ewatrrr,Gogonati)
solve 2log3 +log2x = log(3x+1) Evaluate 2logbase2 4 +3logbase2 5 -log-log2 25-log2... (answered by stanbon)