SOLUTION: 2log5x-log52=log5(2x+6)
the 5's are the base.
can you solve it??
Algebra.Com
Question 130890: 2log5x-log52=log5(2x+6)
the 5's are the base.
can you solve it??
Answer by mathispowerful(115) (Show Source): You can put this solution on YOUR website!
-=
Rewrite it:
- =
Then
=
multiply 2 on both sides you get,
solve this equation
you get
(x-6)(x+2) = 0,
so x = 6, or x=-2.
But negative number is not allowed in this problem,
so the final answer is x=6.
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