SOLUTION: Could someone please show me how to solve this problem x=e^-7.85 my teacher saids the answer is 3.90*10^-4 I can't figure out how she came up with that answer. By the way the -7.

Question 121237This question is from textbook beginning and intermediate algebra
: Could someone please show me how to solve this problem
x=e^-7.85 my teacher saids the answer is 3.90*10^-4 I can't figure out how she came up with that answer. By the way the -7.85 and the -4 are exponents, I couldn't get them to show up right. Thanks for helping. This question is from textbook beginning and intermediate algebra

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
x = e^-7.85
:
Find the nat log of both sides:
ln(x) = ln(e^-7.85)
:
Use the log equivalent of exponents
ln(x) = -7..85*ln(e)
:
We know nat log of e is 1 so we just have:
ln(x) = -7.85
:
Find the anti log of -7.85, that's on the calculator
x = 3.897519683 E -4 is the solution from my calc
:
You can see that it could be written in scientific notation
x = 3.90*10^-4
;
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