SOLUTION: Log4 base2+log9 base3

Question 1209825: Log4 base2+log9 base3
Answer by CPhill(1959) (Show Source): You can put this solution on YOUR website!
Let's evaluate the given expression:
log₄(2) + log<0xE2><0x82><0x89>(3)
**1. Evaluate log₄(2):**
* We want to find the power to which we must raise 4 to get 2.
* 4^(1/2) = √4 = 2
* Therefore, log₄(2) = 1/2
**2. Evaluate log<0xE2><0x82><0x89>(3):**
* We want to find the power to which we must raise 9 to get 3.
* 9^(1/2) = √9 = 3
* Therefore, log<0xE2><0x82><0x89>(3) = 1/2
**3. Add the Results:**
* log₄(2) + log<0xE2><0x82><0x89>(3) = 1/2 + 1/2 = 1
**Therefore, log₄(2) + log<0xE2><0x82><0x89>(3) = 1**

RELATED QUESTIONS
log(base3)3/4 + log(base3)4/5 + log(base3)5/6 + log(base3)6/7 + log(base3)7/8 +... (answered by Fombitz,ikleyn,MathTherapy)

log(base2)log(base3)log(base4)2^n=2 I don't understand how to solve... (answered by stanbon)

use change-of-base formula to find three significant digits. log base2 6+ log base3... (answered by Alan3354)

condense to a single logarithm log9 x+log9 y+log9 z condense to a single logarithm... (answered by Alan3354)

Solve i) {{{log(base3)(2x + 1) = 2 + log (base3) (3x - 11)}}} ii) {{{log(base4)y + log... (answered by lwsshak3)

what is log4 to base2 with the addition of log7 to base2 then subtract logX to base... (answered by drk)

log9 (answered by rapaljer,unlockmath)

Fill in the missing values to make the equations true. The ? are the missing value... (answered by greenestamps)

A. Solve log4 (3x-7)<2 B.Solve log9 (3x-7)>= log9 (2x+9) C. Evaluate (Log4 12^3)... (answered by lwsshak3)