Question 1205462: Log 6 to the base 2+ log 7 to the base 2 equals to log a to the base 2
Solve for a Found 2 solutions by Theo, math_tutor2020:Answer by Theo(13342) (Show Source):
The second rule is valid because the log function of any base is one-to-one aka injective.
Use the lst rule mentioned above
Use the 2nd rule mentioned
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Often it's a pain to repeatedly write "base 2" whether in word form or symbolically.
To avoid this repetition and speed things up, you can state somewhere at the top of your page "all logs mentioned are base 2" or something along those lines.
After that statement you could have your starting equation as:
log(6) + log(7) = log(a)
Just keep in mind that these are base 2 logs of course.
It turns out the base doesn't matter here. The log rules mentioned at the top work for any base as long as it's a positive real number and the base isn't 1. The final answer a = 42 will happen for any valid base.
Bonus exercise: Explain to your classmate why log base 1 isn't valid. A hint is to think about the change of base formula. Another hint is to look at the denominator.