SOLUTION: Show that 3+log2(9)=log2(8)

Question 1205396: Show that 3+log2(9)=log2(8)
Found 3 solutions by ikleyn, math_tutor2020, greenestamps:
Answer by ikleyn(52906)   (Show Source): You can put this solution on YOUR website!
.
Show that 3+log2(9)=log2(8)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

This can not happen because this can never happen.

The Math composer, who created this post (so called Math problem),
deserves very serious reprobation.

From the distance of thousand miles, it is clearly seen
that this person does understand NOTHING in Math.

Answer by math_tutor2020(3817)   (Show Source): You can put this solution on YOUR website!

Used log rule log(A)-log(B) = log(A/B)

Converting from log form to exponential form

We get a contradiction, so the original equation is false.

--------------------------------------------------------------------------

Another way to show the contradiction:

Using log rule log(A^B) = B*log(A) to pull down the exponent.

Log base b of itself is 1.

The 3's cancel when subtracting them from both sides.

Converting from log form to exponential form.

which is a contradiction

Answer by greenestamps(13215)   (Show Source): You can put this solution on YOUR website!

Without doing any work on the problem, it should be clear (if you know anything about logarithms) that log2(9) by itself is greater then log2(8), so 3 + log2(9) can't be equal to log2(8).

The problem is flawed; or you posted it incorrectly....

RELATED QUESTIONS
2log4 9-log2 3 (answered by jrfrunner)
Solve log2... (answered by advanced_Learner,MathTherapy)
Log2 4+ log2... (answered by nerdybill)
Find the exact value of log2 8 - log2 24 log2 8 - log2 24 = x 2^x =8 2^x=24 x= (answered by Edwin McCravy)
Log2(96) -... (answered by Alan3354)
log2 96 - log2... (answered by nerdybill)
Show that... (answered by josmiceli,MathTherapy)
Given log 4^(y-1)+ log4^(8/2) = a+log2^(y+1)-log2^3=a-1. Show that... (answered by greenestamps)
9/4... (answered by jsmallt9)