SOLUTION: 2 ^ log(2,(2x + 3)) + 5^log(5,(x + 7)) = 7 ^ log_7(2x + 18)
Algebra.Com
Question 1204786: 2 ^ log(2,(2x + 3)) + 5^log(5,(x + 7)) = 7 ^ log_7(2x + 18)
Found 2 solutions by MathLover1, Alan3354:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
use log rule:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
2 ^ log_2(2x + 3) + 5 ^ log_5(x + 7) = 7 ^ log_7(2x + 18)
-----------
---
2x+3 + (x+7) = 2x+18
3x + 10 = 2x + 18
x = 8
RELATED QUESTIONS
log(7-2x)=log(x+5) (answered by fractalier)
2 log 7^3+log7^2x=long... (answered by jsmallt9)
log(2x + 3)=log... (answered by nerdybill)
solve for x 2+4(5)^x=16
Solve for x Log of 7 (5x-1)=2
Log of 2 (1- x) - Log of 2... (answered by stanbon)
log x-log 10=14
log (x+9)= log (2x-7)
log x^2+ log... (answered by jsmallt9)
Write as a single log:... (answered by lwsshak3)
log 10x - log (2x - 3) = log 7 solve for... (answered by stanbon)
Solve: log(5)... (answered by Earlsdon)
45. log (x+2)+ log (x-2)=1
5 5
47. log (4x)+ log (x+3)=log x
7 (answered by edjones)