SOLUTION: If a=log4 of 7 and b=log7 of 5, then in terms of a and b, log5 is equal to:
a) ab
b)(2ab+1)/ab
c)2ab/(1+2ab)
d)(4b+a)/7
e)a^2-b^2
Algebra.Com
Question 1197720: If a=log4 of 7 and b=log7 of 5, then in terms of a and b, log5 is equal to:
a) ab
b)(2ab+1)/ab
c)2ab/(1+2ab)
d)(4b+a)/7
e)a^2-b^2
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Multiply:
Solve for log(5):
Convert into an expression with
ANSWER: c)
RELATED QUESTIONS
if a-b=5 and ab=-1, what is the numerical value of... (answered by AnlytcPhil)
1-2ab-(a+b)^2 (answered by It is costly)
If log 3 = a and log 5 = b , then log 75 = ?
a )ab^2
b) 2b+a
c) b^2+a
d) 2ab (answered by josgarithmetic)
1-2ab-(aČ+bČ) (answered by Ed Parker)
For positive numbers a, b, and c, if 2ab = 1, 3bc = 2, and 4ca = 3, what is the value of... (answered by math_tutor2020,ikleyn)
If a^2 - 2ab + b^2 = 36 and a^2 - 3ab + b^2 = 22 what is the value of ab ?
(A) 6 (B) (answered by palanisamy)
If {{{a^2-2ab+b^2=36}}} and {{{a^2-3ab+b^2=22}}} find... (answered by richard1234)
find (x - 7)2
and
which of the following is a pattern for squaring a binomial, a... (answered by checkley75)
(a^2+b^2+2ab)-(a^2+b^2-2ab) (answered by jim_thompson5910)