SOLUTION: Find dy/dx when: 𝑦 = ln(𝑥^3 + 2)(𝑥^2 + 3)

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Question 1197119: Find dy/dx when:
𝑦 = ln(𝑥^3 + 2)(𝑥^2 + 3)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
𝑦 = ln(𝑥^3 + 2)(𝑥^2 + 3)
 Let f = ln(𝑥^3 + 2)  and g = (𝑥^2 + 3) 
 f' = 3x^2/(x^3 + 2)   and g' = 2x
y'=     f(x)g'(x))  +   g(x)f'(x)
y' = +2xln%28x%5E3+%2B+2%29+%2B++%28x%5E2%2B3%29%283x%5E2%2F%28x%5E3+%2B+2%29+%29+ 
y' = %283x%5E2%29+%28x%5E2%2B3%29%2F%28x%5E3+%2B+2%29+%2B+2xln%28x%5E3+%2B+2%29+%29+ 
     

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