SOLUTION: Find dy/dx when: 𝑦 = ln(𝑥^3 + 2)(𝑥^2 + 3)

Algebra.Com
Question 1197119: Find dy/dx when:
𝑦 = ln(𝑥^3 + 2)(𝑥^2 + 3)

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
𝑦 = ln(𝑥^3 + 2)(𝑥^2 + 3)
 Let f = ln(𝑥^3 + 2)  and g = (𝑥^2 + 3) 
 f' = 3x^2/(x^3 + 2)   and g' = 2x
y'=     f(x)g'(x))  +   g(x)f'(x)
y' =  
y' =  
     

Wish You the Best in your Studies.

RELATED QUESTIONS

Find dy/dx using the method of logarithmic differentiation when y = (4+9x^2)^ln(x)... (answered by Edwin McCravy)
Given that dy/dx=a/x^2+1 and that when x=1 dy/dx=3 and y=3 find the value of y when... (answered by solver91311)
Given that dy/dx=a/x^2 +1 and that when x=1 dy/dx=3 and y=3 find the value of y when... (answered by solver91311)
find dy/dx y=2 ln... (answered by jim_thompson5910)
find dy/dx e^xy-ex^3 =... (answered by venugopalramana)
Find dy/dx for x^3+2xy^2 = sin... (answered by ikleyn,Edwin McCravy)
Find the value of {{{(dy)/(dx)}}} when x= -1 and y= 1, given that {{{3x^2+4xy-xy^3 =... (answered by ikleyn)
if dy/dx = sec(x) , dt/dx = tan(x) - 3, then ,(d ^2 y)/(dt ^2) =... when(x =... (answered by mccravyedwin)
Please find dy/dx using implicit differentiation: y^2+e^y=ln x^2+4... (answered by funmath)