SOLUTION: Show that whenever n ≥ 3, fn > ßn-2 , where ß = (1 + √ 5)∕2.
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Question 1192804: Show that whenever n ≥ 3, fn > ßn-2 , where ß = (1 + √ 5)∕2.
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
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Show that whenever n ≥ 3, fn > ßn-2 , where ß = (1 + √ 5)∕2.
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Makes no sense.
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To the managers of this project ( ! )
As I notice, nonsensical messages arrive to this forum, created by persons illiterated in Math.
Examples are these posts
https://www.algebra.com/algebra/homework/logarithm/logarithm.faq.question.1192804.html
https://www.algebra.com/algebra/homework/Linear-equations/Linear-equations.faq.question.1192802.html
https://www.algebra.com/algebra/homework/Pythagorean-theorem/Pythagorean-theorem.faq.question.1192801.html
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I ask you please to take all necessary measures and remove the person/(persons) who created these posts
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