SOLUTION: Given log 4^(y-1)+ log4^(8/2) = a+log2^(y+1)-log2^3=a-1. Show that y^2+1+8^a
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Question 1190620: Given log 4^(y-1)+ log4^(8/2) = a+log2^(y+1)-log2^3=a-1. Show that y^2+1+8^a
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
"Show that y^2+1+8^a"
That makes no sense. The thing to be shown needs to be an equation of some sort -- not just an expression.
And you're probably better off using different notation for logarithms -- e.g. "log4(y-1)" instead of "log 4^(y-1)". "^" in typed text denotes exponents -- not logs.
Re-post....
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