SOLUTION: Answer the following logarithmic inequalities. 1) log3(1-x)>=log3(x+16-x^2) (Note: 3 is a base) Thank you.

Algebra.Com
Question 1189456: Answer the following logarithmic inequalities.
1) log3(1-x)>=log3(x+16-x^2)
(Note: 3 is a base)
Thank you.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Duplicate.
Was solved in great detail earlier today.
Look at solved problems.

RELATED QUESTIONS

Answer the following logarithmic inequalities. 1) log3(1-x)>=log3(x+16-x^2) (Note:... (answered by Theo,greenestamps)
Log3(x+1)-log3(x)+log3(3) (answered by Alan3354)
What is (log3 x)^2 = log3 x^2 + 3. The answer in the answers part is 27 and 1/3. Thank... (answered by khwang)
Log3(1-x)=log3(x+16-x^2) (answered by Edwin McCravy)
Solve for x. log3(x+7)=2-log3(x-1) Write the exact answer using base-10... (answered by jsmallt9)
Solve the logarithmic equation for x. log3 4 + log3 x = log3 6 + log3(x −... (answered by stanbon,nakaguma)
log3(x-2) = 1+log3(x-4) The logs have a base of 3. How do I solve... (answered by scott8148)
log3 (x+2) + log3 (x-2) =... (answered by stanbon)
log3 (x+2) + log3(x-2) =... (answered by solver91311)