SOLUTION: log(x+6) < log(3-2x)

Algebra.Com
Question 1188644: log(x+6) < log(3-2x)
Answer by ikleyn(52817)   (Show Source): You can put this solution on YOUR website!
.
log(x+6) < log(3-2x)
~~~~~~~~~~~~~~~~~~~~~~~~~

Your staring inequality is

    log(x+6) < log(3-2x).


First, determine the domain, i.e. the set of real numbers, where this inequality makes sense.


Logarithm must have positive arguments:  x+6 > 0  and  3-2x > 0.

First inequality gives  x > - 6;  the second inequality gives  3 > 2x,  or   x < 1.5.


So, the domain is this set  -6 < x < 1.5.     (1)



Next, logarithm is monotonic function; therefore, from the given inequality we have

    x + 6 < 3 - 2x.


Simplify it

    x + 2x < 3 - 6

      3x   <   -3

       x   <   -1.


Comparing the domain (1) with the last inequality, we see that the solution to the problem is this set

    -6 < x < -1.

Solved.



RELATED QUESTIONS

log x^5 - Log x^3 = log 6x - log... (answered by Fombitz)
Log(2) (2x+6) - log(2) x=... (answered by ewatrrr)
log(2x+6)+log(x-2)=2 (answered by nerdybill)
log(x-2)+log(2x-3)=2Logx (answered by vleith)
log(2x-1) = log(x+3) +... (answered by jim_thompson5910)
Log(x-3) + log(2x + 1) =... (answered by nerdybill)
log(2x+3)=log(x-2) (answered by Alan3354)
log(2x)-log(x-3)=1 (answered by edjones)
3 log x + log... (answered by Fombitz)