SOLUTION: "can u pls. help me write the following exponential equations in logarithmic form?" 1.7^x=49 2.6^-3=(1/126) 3.12^2=144 also this...find the value of the following logarithmic exp

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Question 1187994: "can u pls. help me write the following exponential equations in logarithmic form?" 1.7^x=49 2.6^-3=(1/126) 3.12^2=144 also this...find the value of the following logarithmic expressions. 1.log3 243 2.log6 (1/216) 3.log0.25 16 thank u so much for the help.
Found 3 solutions by MathLover1, MathTherapy, greenestamps:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
1.










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2.

=> assuming you have

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3.

=> assuming you have







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1.

2.

3.


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

"can u pls. help me write the following exponential equations in logarithmic form?" 1.7^x=49 2.6^-3=(1/126) 3.12^2=144 also this...find the value of the following logarithmic expressions. 1.log3 243 2.log6 (1/216) 3.log0.25 16 thank u so much for the help.
This is in no way as COMPLEX as that woman made it out to be.


If you need a value, then just enter that into a calculator. 
If it's difficult to enter, then just enter the change-of-base version: 
You can now do nos. 2 & 3 the same way.


The value of the following logarithmic expression: 
Enter the above into a calculator. 
Again, if it's difficult to do so, then just enter the change-of-base version: 
If you need to calculate without a calculator, then do the following:
  ----- Setting  equal to x
 ----- Converting to EXPONENTIAL form
 ------ Converting 243 to base 3
  ------ Bases are equal and so are their exponents

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


I suspect the way you posted the problems misled the other tutors. Very probably the first set of three problems are these:

(1)

(2) <-- that one includes a typo -- you showed 1/126....

(3)

To convert each of those to logarithmic form, all you need to remember is this:

THE LOGARITHM IS THE EXPONENT

(1) The exponent is x; obviously the base is 7 --> "log (base 7) of 49 is x" -->

(2) The exponent is -3; the base is 6 --> "log (base 6) of 1/216 is -3" -->

(3) The exponent is 2; the base is 12 --> "log (base 12) of 144 is 2" -->

For the other problems you again only need to remember the same thing.

(1) --> "log (base 3) of 243 is x" --> THE LOGARITHM (x) IS THE EXPONENT -->

(2) --> "log (base 6) of 1/216 is x" --> THE LOGARITHM (x) IS THE EXPONENT -->

(3) --> "log base 0.25 of 16 is x" --> THE LOGARITHM (x) IS THE EXPONENT -->

I leave it to you to find the values of x for those last three problems.


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