SOLUTION: what is the value of x when the equation is log5+logx=2?

Question 118700: what is the value of x when the equation is log5+logx=2?
Found 2 solutions by m.hansen, Earlsdon:
Answer by m.hansen(16) (Show Source): You can put this solution on YOUR website!
log5+logx=2?
remember: logs can be combined as such: Log(x) + Log(y) -> Log(x*y)
so: log(5) + log(x) = 2
becomes: log(5*x)=2 or log(5x)=2
logs can be changed into exponents, and "log" is base 10.
so: log(5x)=2 becomes: 5x= {10^2} (10^2 = 10 squared)
5x= {10^2}
5x=100
divide both sides by 5
x=20
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Find the value of x:
Apply the "product rule" for logarithms:
to get:
Rewrite this in "exponential" form: ---> to get:
Divide both sides by 5:
so...

Check:
= 2
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