SOLUTION: given that log2 = 0.3010, log3= 0.4771 and log7= 0.8451 evaluate 1.log(14/3) 2.log (7/2)

Algebra.Com
Question 1184680: given that log2 = 0.3010, log3= 0.4771 and log7= 0.8451
evaluate
1.log(14/3)
2.log (7/2)

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
given that log2 = 0.3010, log3= 0.4771 and log7= 0.8451
evaluate
1.log(14/3) = log(2) + log(7) - log(3)
===================
2.log (7/2) = log(7) - log(2)

RELATED QUESTIONS

given log 7=0.8451 and log 2 =0.3010, find the value of log 28. (answered by Alan3354,Theo,ikleyn,MathTherapy)
please help me Evaluate the following.... (answered by ikleyn)
given log2=.3010, log7= .845, and log3=.4771 find the values of: 1)log28 2)log... (answered by josmiceli)
11) Given log a = 0.3010 and log b = 0.4771, evaluate log 24... (answered by josgarithmetic,greenestamps)
1. Identify the equation that represents the function in the following graph. (answered by Alan3354)
Given that log2=0.3010, log7=0.845 and log5=0.699 Evaluate... (answered by ikleyn)
Given log 2=.3010 and log 3=.4771, evaluate log 6 Can you multiply the logs to get the... (answered by MathTherapy)
Given Log 2=.3010 and log 3 =.4771, find: a. log (240) b. log... (answered by jsmallt9)
if log10^2=0.3010 and log10 ^7=0.8451.Evaluate "1" log10 ^0.2 "2" log10^35^2 without... (answered by math_tutor2020,Alan3354,ikleyn)