SOLUTION: Complete the table for a savings account in which interest is compounded continuously. (Round your answers to four decimal places.) Initial Investment = $300 Amount after 14 y

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Question 1183340: Complete the table for a savings account in which interest is compounded continuously. (Round your answers to four decimal places.)
Initial Investment = $300
Amount after 14 years = $385.21
I found the annual rate to be 1.7858%
I am looking for the time to double(in years). I figured it to be 38.8144 but this answer is incorrect. Please help!

Found 2 solutions by ankor@dixie-net.com, Solver92311:
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
Complete the table for a savings account in which interest is compounded continuously. (Round your answers to four decimal places.)
Initial Investment = $300
Amount after 14 years = $385.21
:
the formula
= A
so we have
= 385.21
So that is right
:
I am looking for the time to double(in years).
= 600
or
= 2
.017858t = ln(2)
t = 38.8 yrs, I think you are right, unless they want you to round up to 39 yrs


Answer by Solver92311(821)   (Show Source): You can put this solution on YOUR website!


You shouldn't have rounded your interest rate calculation before you used it in the time-to-double calculation. Try 38.8153 years. Then tell your instructor to pull his or her head out of his or her ass for wanting more than one digit precision for such a calculation. The difference between your answer and the "correct" one is just shy of 8 hours. Who in their right mind would give a rat's patoot about 8 hours when you are talking about almost 39 years?


John

My calculator said it, I believe it, that settles it

From
I > Ø

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