SOLUTION: logx+log(x+1)=log2

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Question 1176133: logx+log(x+1)=log2
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!




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Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
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logx + log(x+1) = log2
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            Ignore writing by @josgarithmetic,  since it is wrong.

            I came to bring the correct solution. 


From

    log(x) + log(x+1) = log(2)


you have


    log(x*(x+1)) = log(2)

    x*(x+1) = 2


From this point, you may guess both the roots   x= 1  and  x= -2.


    //  If you do not like guessing, you may solve this quadratic equation formally.


Negative x does not fit to logarithm, therefore you get the UNIQUE solution 

         x = 1.        ANSWER

Solved.



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