ln{[(𝑥^15)(x-1)^1/2]/(3x-16)}=𝐴ln𝑥+𝐵ln(𝑥−1)+𝐶ln(3𝑥−16)
1)with the constant A=?
2)the constant B=?
3)and the constant C=?
= Aln(x) + Bln(x - 1) + Cln(3x - 16)
= Aln(x) + Bln(x - 1) + Cln(3x - 16)
= Aln(x) + Bln(x - 1) + Cln(3x - 16)
15ln(x) + ln(x - 1) - 1ln(3x - 16)
Aln(x) + Bln(x - 1) + Cln(3x - 16)
Comparing coefficients above, we see that