SOLUTION: 2log1/8+3log1/4+log1/2+log2+3log4+2log8

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Question 1159551: 2log1/8+3log1/4+log1/2+log2+3log4+2log8
Found 2 solutions by solver91311, ikleyn:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


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John

My calculator said it, I believe it, that settles it


Answer by ikleyn(52873)   (Show Source): You can put this solution on YOUR website!
.

ANSWER. 2log(1/8) + 3log(1/4) + log(1/2) + log(2) + 3log(4) + 2log(8) = 0.



Explanation.


    log(1/8) = -log(8)

    log(1/4) = -log(4)

    log(1/2) = -log(2)

Solved.

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On logarithms and their properties,  see these introductory lessons
    - WHAT IS the logarithm
    - Properties of the logarithm
    - Change of Base Formula for logarithms
    - Evaluate logarithms without using a calculator
    - Simplifying expressions with logarithms
    - Solving logarithmic equations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Logarithms".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.



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