SOLUTION: A bacteria culture initially contains 1500 bacteria and doubles every half hour. Find the size of the baterial population after 100 minutes. Find the size of the bateri

Question 1159087: A bacteria culture initially contains 1500 bacteria and doubles every half hour.
Find the size of the baterial population after 100 minutes.

Find the size of the baterial population after 4 hours.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!

p, initial size
x, number of HOURS passed

If p is 1500 then .

100 minutes is 60 minutes plus 40 minutes, or hours.

after 100 minutes
Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.

            The solution and the answer (of 48000 bacteria population) by @josgarithmetic are INCORRECT.

            I came to bring the correct solution/answer.

N = 1500*2^(t/0.5) = 1500*2^(2t), where " t " is the time in hours. t = 100 minutes = hours = hours. Therefore, after 100 minute, the bacteria population is N = 1500*2^(2*(5/3)) = 1500*2^(10/3) = 15119. ANSWER 4 hours are 8 doubling periods. Therefore, after 4 hours, the bacteria population is N = 1500*2^8 = 384000. ANSWER

Solved.

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