SOLUTION: Solve for x: x= radical 2x-7+5 I have worked the problem (x-5)^2 =2x-7 x=8 and x=4 But I don't know how to do the check, can you help?

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Question 115756: Solve for x: x= radical 2x-7+5
I have worked the problem
(x-5)^2 =2x-7
x=8 and x=4
But I don't know how to do the check, can you help?
Answer by jim_thompson5910(21667) About Me  (Show Source):
You can put this solution on YOUR website!
x=sqrt%282x-7%29%2B5 Start with the given equation


8=sqrt%282%288%29-7%29%2B5 Plug in the first solution x=8


8=sqrt%2816-7%29%2B5 Multiply


8=sqrt%289%29%2B5 Subtract


8=3%2B5 Take the square root of 9 to get 3


8=8 Add. Since both sides of the equation are equal, x=8 is a valid solution


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x=sqrt%282x-7%29%2B5 Start with the given equation


4=sqrt%282%284%29-7%29%2B5 Plug in the second solution x=4


4=sqrt%288-7%29%2B5 Multiply


4=sqrt%281%29%2B5 Subtract


8=1%2B5 Take the square root of 1 to get 1


8%3C%3E6 Add. Since both sides of the equation are not equal, x=4 is a not valid solution


So the only solution is x=8