From the given equation, (x-2)*(x-6) = 5. (1) The numbers, whose product is 5 and that differ 4 units, are the pairs (1,5) and (-1,-5). So, x-2 = 5, x = 5 + 2 = 7 is one solution, while x-2 = -1, x = 1 is formally another solution to the quadratic equation (1). But under the logarithm, only the solution x = 7 survives. ANSWER. x = 7 is the ONLY solution to the given logarithmic equation.