SOLUTION: Log8x+log4(1/6)=1/3

Question 1151062: Log8x+log4(1/6)=1/3
Found 3 solutions by Alan3354, MathLover1, greenestamps:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Log8x+log4(1/6)=1/3
=============
Log(8x) + log(4(1/6)) = 1/3

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

........common denominator

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!

Convert the log base 8 and the log base 4 to logs base 2:

Convert the expression on the left to a single log base 2 using rules of logarithms:

Convert the logarithmic equation to exponential form:

Isolate the term with the variable:

Cube both sides of the equation:

RELATED QUESTIONS
log25-log8x=1... (answered by josmiceli,MathTherapy)
log8x+log64(x+2)=1 (answered by lwsshak3)
log4(y + 3) − log4(y − 1) = log4... (answered by Alan3354)
log4 x-log4 (x+3)= -1 (answered by solver91311,Alan3354)
log4 (x2-3) + log4... (answered by stanbon)
Log8x+log4x+log2x=1 prove... (answered by Alan3354)
log4[log4(2x)]=1 (answered by math_helper)
Solve the equation: log4 30-log4(x-1)-log4(x+2)=log4... (answered by lwsshak3)
solve for x... (answered by nerdybill)