SOLUTION: Log[log(2+log2(x+1))]=0
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Question 1148553: Log[log(2+log2(x+1))]=0
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Log[log(2+log2(x+1))]=0
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log(2+log2(x+1)) = 1
2+log2(x+1) = 10
log2(x+1) = 8
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Not clear.
Is it log(2*(x+1)) = 8 ?
Put the arguments of logs in parentheses.
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