SOLUTION: Solve the following: log(z^2-25)-log(z+5)=log7

Algebra.Com
Question 114805: Solve the following:
log(z^2-25)-log(z+5)=log7

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


First notice that is the difference of two squares, so . But we also know that the log of the product is the sum of the logs of the factors (), so we can write:



Since , our equation reduces to:



Since if and only if , we can now write:


Done.



RELATED QUESTIONS

Hi, I am having a problem solving: log(z^2-25)-log(z+5)=log7 The farthest I... (answered by solver91311,Alan3354)
Condense the following single logarithmic. 5 log x -2 log y +8 log z-3 log w (answered by user_dude2008)
Solve the following: log(7)24−log7(x+5)=log(7)8... (answered by harpazo)
log base 5 of... (answered by josmiceli)
{{{ (log((z)))^2=log((z^2))... (answered by lwsshak3,stanbon)
Knowing that x = log(base a)2 , y = log(base a)3, z=log(base a)5 express the following... (answered by lwsshak3)
Determine the larger root of the following equation: log(z) + log(z + 19) = 2 log(z +... (answered by ankor@dixie-net.com)
simplify expression into a single log 1/3... (answered by nerdybill)
Please help! I would really appreciate it! >Solve the equation (1/3)log7 64+ (1/2)log7 (answered by solver91311)