SOLUTION: How to solve for x in the equation log(sub 5)(x+4) + log(sub 5)(x) = 2

Question 114690: How to solve for x in the equation
log(sub 5)(x+4) + log(sub 5)(x) = 2
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
log(5)(x+4)+log(5)x=2
log(5)(x(x+4))=2
log(5)(x^2+4x)=2
x^2+4x=5^2
x^2+4x-25=0
x=3.38516... Quadratic formula (see below)
Ed

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=116 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 3.3851648071345, -7.3851648071345. Here's your graph:

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