SOLUTION: Solve: 3^(x^2+4x) = 1/27

Algebra.Com
Question 114400: Solve: 3^(x^2+4x) = 1/27
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
3^(x^2+4x) = 1/27
-------------------
3^(x^2+4x) = = 3^-3
x^2+4x = -3
x2+4x+3=0
(x+3)(x+1) = 0
x = -3 or x= -1
===================
Cheers,
Stan H.

RELATED QUESTIONS

Solve a) 3^(x^2+4x) = 1/27 Can you please help me out? Thanks so much in... (answered by josmiceli)
solve for x: 3^x-2=1/27 (answered by lwsshak3)
solve 27^x-1 =... (answered by Fombitz)
Solve the equation... (answered by swincher4391)
Exponential equations without using logs. Solve for x: 3^(4x+1)=... (answered by stanbon)
Solve 9^x^2=27^x+3 Solve... (answered by Fombitz)
Solve 2(4x + 3) = 10(x +... (answered by jim_thompson5910)
solve... (answered by lwsshak3)