SOLUTION: Given that log2=0.3010 and log3=0.4771, find log12 using log rules (not calculator)
Algebra.Com
Question 1143851: Given that log2=0.3010 and log3=0.4771, find log12 using log rules (not calculator)
Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39630) (Show Source): You can put this solution on YOUR website!
Make the given substitutions and evaluate.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Given that log2=0.3010 and log3=0.4771, find log12 using log rules
---------
12 = 2*2*3
Log(12) = log(2) + log(2) + log(3)
RELATED QUESTIONS
given that log2 = 0.3010, log3= 0.4771 and log7= 0.8451
evaluate
1.log(14/3)
2.log (answered by Alan3354)
If log2=.3010 and log 3=.4771 then find... (answered by greenestamps)
11) Given log a = 0.3010 and log b = 0.4771, evaluate log 24... (answered by josgarithmetic,greenestamps)
given log2=.3010, log7= .845, and log3=.4771 find the values of:
1)log28
2)log... (answered by josmiceli)
Given log10 2=.3010 and log10 3=.4771, find each logarithm without using a calculator.
(answered by nerdybill)
Given Log 2=.3010 and log 3 =.4771, find:
a. log (240)
b. log... (answered by jsmallt9)
if Log2=.3010 and log3=.4771, then find
(A) log1/25 (b) log3.002
(answered by Alan3354)
Given that... (answered by ikleyn)
Given that log5=0.699 and log 3=0.4771 find 45
(answered by Edwin McCravy)