SOLUTION: I need to find the value of v in the following log. v=log(base 2)(1/4) If I do as the law says, I come up with -2. But the book is showing 22. Am I doing this wrong or is t

Question 1140: I need to find the value of v in the following log.
v=log(base 2)(1/4)
If I do as the law says, I come up with -2. But the book is showing 22. Am I doing this wrong or is the books answer wrong.
Answer by khwang(438) (Show Source): You can put this solution on YOUR website!
If v=log(base 2)(1/4), by definition of log,
2^v = 4.
Now if v= -2, 2^(-2) = 1/2^2 = 1/4
So your answer is correct.
One way to solve:
v = log(base 2)(1/4) = -log(base 2)4 = -log(base 2) 2^2
= - 2 log(base 2) 2 = -2 * 1 = -2.

RELATED QUESTIONS
Please help me with these four questions in the review section. Find the value of... (answered by fractalier)

How do I come up with the answer to this problem 2 5/2 - 2 3/2. I have tried everything... (answered by fcabanski)

I need the help on Log Use the properties of logarithms to find the exact value of the (answered by nerdybill)

Hi. I'm am required to find x in this equation: {{{log (5, (5-4x))}}} = {{{log (sqrt(5),... (answered by Earlsdon)

I do not understand why Log base 2 to the number = 0. (why Log(2) = 1) (answered by edjones)

{{{-2=log(v, 1/100)}}} I have changed it to {{{v^-2=(1/100)}}} but am stuck as to what (answered by ewatrrr,solver91311)

Hi I need help with this question: Evaluate log to the base 2,(2x+1) - log to the base (answered by lwsshak3)

What is the value of x in log base x (log base 2(log base 2(log base x 9) = 0? I need ur (answered by josmiceli)

I just need someone to explain this and why 2 is the answer: 3^(log base 9 (4))= 2... (answered by solve_for_x,josgarithmetic,ikleyn,MathTherapy)