SOLUTION: Solve:
1) 5^2X^2^+^3X=25
2) 3^-X=7^X+^2
3) 250000=100000(1+.06/12)^12(t)
Algebra.Com
Question 1139283: Solve:
1) 5^2X^2^+^3X=25
2) 3^-X=7^X+^2
3) 250000=100000(1+.06/12)^12(t)
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
1) 5^2X^2^+^3X=25
The sequence of characters "X^2+^" has no meaning.
The sequence of characters "+^3" has no meaning.
2) 3^-X=7^X+^2
The sequence of characters "+^2" has no meaning.
3) 250000=100000(1+.06/12)^12(t)
The equation as you show it is solved by ordinary arithmetic....
The value of t is 250000, divided by the product of 100000 and (1+.06/12)^12.
Surely you meant
3) 250000=100000(1+.06/12)^(12t)
This is now an equation for finding the number of years t that it takes 100000 to increase to 250000 at 6% compounded monthly.
The variable is in the exponent; you need to take logs of both sides.
Use a calculator....
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