SOLUTION: log base3 (x+2)+log base3(x-3)=4

Question 1139093: log base3 (x+2)+log base3(x-3)=4
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!

adding logs is multiply

FOIL

The exponent equiv
x^2-x-6 =
x^2 - x - 6 = 81
x^2 - x - 6 - 81 = 0
x^2 - x - 87 = 0
use the quadratic formula; a=1; b=-1; c=-87
the positive solution only
x = 9.841
RELATED QUESTIONS
Please help. log base3(x-2)+log base3(x+4)=3 e^x+5=8 (answered by Earlsdon)

log base3 x +log base3 (x-4)... (answered by Earlsdon)

log(Base3)(x-1)... (answered by rapaljer)

1/2 log base3 X= 2 log base3 2 (answered by edjones)

log (base3) x = 1/2 log (base3) 25 - 5 log (base3)... (answered by Susan-math)

Log(base3)27=x (answered by josmiceli)

Expand... (answered by lwsshak3)

Use properties of logarithms to solve the equation log(base3)x + log(base3)(x + 2) =... (answered by ankor@dixie-net.com)

express as a logarithm of a single number: 1. log basex 20 + logbasex 2 2. 3 log... (answered by lwsshak3)